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For the beam of Problem 8.27, determine the maximum positive and negative shears and the maximum positive and negative...
For the beam shown in Fig. 9.5(a), determine the maximum positive and negative shears and the...
For the beam shown in Fig. 9.5(a), determine the maximum positive and negative shears and the maximum positive and negative bending moments at point due to a concentrated live load of 90 kN, a uniformly distributed live load of 40 kN/m, and a uniformly distributed dead load of 20 kN/m. А B с 3 m - 3 m 6 m (a) cm | قمة | А с D B D A B -2 (e) Influence Line for Mc (kN-m/kN) (b)...
Question 1 (30 points) Hinge Hinge Draw the influence lines for A) reaction moment at G...
Question 1 (30 points) Hinge Hinge Draw the influence lines for A) reaction moment at G b) shear and bending moment at E c) Determine the maximum positive and negative shears and the maximum positive and negative bending moments at point E due to (i concentrated live load of 160 kN, (ii) uniformly distributed live load of 28 kN/m with 2 m length
Using muller principle, draw a 5 m 6 m a) sShear & bending moment at point...
Using muller principle, draw a 5 m 6 m a) sShear & bending moment at point C b) Determine the maximum positive and negative shears and the maximum positive and negative bending moments at point C due to (i) concentrated live load of 150 kN (ii) uniformly distributed live load of 50 kN/m, and (iii) the uniformly distributed live load of 50 kN/m with 4 m length
Problem 1 (30 pts) Problem Statement A propped cantilever beam, with an internal hinge at D,...
Problem 1 (30 pts) Problem Statement A propped cantilever beam, with an internal hinge at D, is shown below. The beam is subject to a uniformly distributed dead load equal to 10 klf, uniformly distributed live load of 20 klf, and a point live load of 30 kips. Determine: 1. The influence line for the moment at A, the moment at C, and the moment reaction at E by applying either the brute-force or equilibrium approach. Find the max positive...
i) For the beam shown in Fig. 1, if the live load on the beam is...
i) For the beam shown in Fig. 1, if the live load on the beam is 20 k/ft and the dead load including the self-weight is 15 k/ft, 1. how to distribute the load in order to get: a) maximum positive moment and b) maximum negative moment. 2. calculate the values of maximum positive and negative moments 3. suggest the locations of the longitudinal steel bars? 20 ft 5 ft
6b. For the beam shown (Type II), using IL diagrams, find at C (i) Maximum negative...
6b. For the beam shown (Type II), using IL diagrams, find at C (i) Maximum negative moment; and (ii) Maximum positive shear, due to concentrated Live Load of 100 kN and an uniformly distributed moving load of 50 kN/m. Dead load is 20 kN/m. (15) -2m- 4m 4 m-
Problem 5 (20 %) The beam below was loaded with uniform load of 3kip/ft. Using the...
Problem 5 (20 %) The beam below was loaded with uniform load of 3kip/ft. Using the Muller-Breslau principle draw the influence lines for bending moment at critical points G and just right of B, considering a unit moving load. (G is located at the mid-span of AB). Calculate the maximum magnitude bending moment at B and at G if a) the uniform load of 3kip/ft is live and b) the uniform load of 3kip/ft is dead. NOTE: Dead loads are...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam must support its own weight and must carry the following loading: Super-imposed distributed dead load = 0.25 kip/ft Distributed live load = 1 kip/ft Concentrated dead load = 12 kip The beam span L = 26 ft and the distance of the concentrated load from the right support a=6 ft. Consider analy- sis of beam subjected to load combination 1.2 dead + 1.6 live....
PLEASE SHOW WORK. WILL UPVOTE! Only need Shear & Moment Diagrams 5) A 30 foot long...
PLEASE SHOW WORK. WILL UPVOTE! Only need Shear &
Moment Diagrams
5) A 30 foot long simply-supported beam supports the unfactored loads shown in the figure. The uniformly distributed dead load, wo, includes the self-weight of the beam, and is constant along the full beam length. Two different uniformly distributed live loads, wuu and wiz are applied as indicated. Concentrated dead, PD, and live, Pt, loads are applied as shown in the figure. Draw factored shear force and factored bending...
(Influence Line Use) Problem 2. The INFLUENCE LINES ARE GIVEN for the beam below. DRAW THE...
(Influence Line Use) Problem 2. The INFLUENCE LINES ARE GIVEN for the beam below. DRAW THE PLACEMENT OF THE LOADS AND CALCULATE THE VALUES FOR THE MAXIMUM NEGATIVE SHEAR at "B", and MAXIMUM POSITIVE MOMENT at "B" due to a concentrated point load of 1400 lb, uniform live load of 800 lb/ft, and a uniform dead load of 600 lb/ft. (12 points) B с 10 ft 6 ft 2A 2 ft Vs ww 2.25 IL RA -0.25 1.25 0.25 IL...
For the beam shown in Fig. 9.5(a), determine the maximum positive and negative shears and the maximum positive and negative bending moments at point due to a concentrated live load of 90 kN, a uniformly distributed live load of 40 kN/m, and a uniformly distributed dead load of 20 kN/m. А B с 3 m - 3 m 6 m (a) cm | قمة | А с D B D A B -2 (e) Influence Line for Mc (kN-m/kN) (b)...
Question 1 (30 points) Hinge Hinge Draw the influence lines for A) reaction moment at G b) shear and bending moment at E c) Determine the maximum positive and negative shears and the maximum positive and negative bending moments at point E due to (i concentrated live load of 160 kN, (ii) uniformly distributed live load of 28 kN/m with 2 m length
Using muller principle, draw a 5 m 6 m a) sShear & bending moment at point C b) Determine the maximum positive and negative shears and the maximum positive and negative bending moments at point C due to (i) concentrated live load of 150 kN (ii) uniformly distributed live load of 50 kN/m, and (iii) the uniformly distributed live load of 50 kN/m with 4 m length
Problem 1 (30 pts) Problem Statement A propped cantilever beam, with an internal hinge at D, is shown below. The beam is subject to a uniformly distributed dead load equal to 10 klf, uniformly distributed live load of 20 klf, and a point live load of 30 kips. Determine: 1. The influence line for the moment at A, the moment at C, and the moment reaction at E by applying either the brute-force or equilibrium approach. Find the max positive...
i) For the beam shown in Fig. 1, if the live load on the beam is 20 k/ft and the dead load including the self-weight is 15 k/ft, 1. how to distribute the load in order to get: a) maximum positive moment and b) maximum negative moment. 2. calculate the values of maximum positive and negative moments 3. suggest the locations of the longitudinal steel bars? 20 ft 5 ft
6b. For the beam shown (Type II), using IL diagrams, find at C (i) Maximum negative moment; and (ii) Maximum positive shear, due to concentrated Live Load of 100 kN and an uniformly distributed moving load of 50 kN/m. Dead load is 20 kN/m. (15) -2m- 4m 4 m-
Problem 5 (20 %) The beam below was loaded with uniform load of 3kip/ft. Using the Muller-Breslau principle draw the influence lines for bending moment at critical points G and just right of B, considering a unit moving load. (G is located at the mid-span of AB). Calculate the maximum magnitude bending moment at B and at G if a) the uniform load of 3kip/ft is live and b) the uniform load of 3kip/ft is dead. NOTE: Dead loads are...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam must support its own weight and must carry the following loading: Super-imposed distributed dead load = 0.25 kip/ft Distributed live load = 1 kip/ft Concentrated dead load = 12 kip The beam span L = 26 ft and the distance of the concentrated load from the right support a=6 ft. Consider analy- sis of beam subjected to load combination 1.2 dead + 1.6 live....
PLEASE SHOW WORK. WILL UPVOTE! Only need Shear &
Moment Diagrams
5) A 30 foot long simply-supported beam supports the unfactored loads shown in the figure. The uniformly distributed dead load, wo, includes the self-weight of the beam, and is constant along the full beam length. Two different uniformly distributed live loads, wuu and wiz are applied as indicated. Concentrated dead, PD, and live, Pt, loads are applied as shown in the figure. Draw factored shear force and factored bending...
(Influence Line Use) Problem 2. The INFLUENCE LINES ARE GIVEN for the beam below. DRAW THE PLACEMENT OF THE LOADS AND CALCULATE THE VALUES FOR THE MAXIMUM NEGATIVE SHEAR at "B", and MAXIMUM POSITIVE MOMENT at "B" due to a concentrated point load of 1400 lb, uniform live load of 800 lb/ft, and a uniform dead load of 600 lb/ft. (12 points) B с 10 ft 6 ft 2A 2 ft Vs ww 2.25 IL RA -0.25 1.25 0.25 IL...
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