Question

Using muller principle, draw a 5 m 6 m a) sShear & bending moment at point C b) Determine the maximum positive and negative shears and the maximum positive and negative bending moments at point C due to (i) concentrated live load of 150 kN (ii) uniformly distributed live load of 50 kN/m, and (iii) the uniformly distributed live load of 50 kN/m with 4 m length

Answer 1

Maximum positive shear = 1/2 times 150 = 75 kn maximum negative shear = -7/ 10 times 150 = -105 KN maximum positive moment = (24/10) times 150 Maximum negative moment = 21/5 times 150 = 630 (ii) Maximum positive shear = 1 /2 times 50 times 5 = 125 KN Maximum Negative shear = -1 /2 times 7 /10 times 50z - 17.5 KN Maximum +ve moment = (1/ 2 times 10 times 24/10) times 50 Maxi -ve moment = 1 /2 (-11/5) times 7 times 50 Maximum +ve shear = (1 /2 + 1 /10] times 4 times 50 maximum -ve shear + [3 /10 + 7/10} 7 times 50 maximum +ve moment = 1/1 Maximum +ve moment = [[1.44 + 2.4/2) times 2.4 times 50] times 2 = 460.8 Km