Homework Answers
KIO3 + 5KI + 6HCl + 6Na2S2O3 -------> 6KCl + 3H2O + 3Na2S4O6 + 6NaI
1 mole 6 moles
KClO3 Na2S2O3
M1 = 0.0104M M2 =
V1 = 25ml V2 = 17.27ml
n1 = 1 n2 =6
M1V1/n1 = M2V2/n2
M2 = M1V1n2/V2n1
= 0.0104*25*6/17.27*1 = 0.09M
The molar concentration of the Na2S2O3 solution = 0.09M >>>>answer
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