Reaction between KIO3 and KI in acidic medium
net ionic equation
IO3- + 5I- + 6H+ ---------> 3 IO2 + 3H2O
reaction between I2 with thiosulphate
Na2S2O3 -------> 2Na+ + S2O3-2
3I2 + 6 S2O3-2 -------> 6I- + S4O6-2
net reaction IO3- + 6H+ + 6 S2O3-2 --------> I- + 3S4O6-2 + 3H2O
moles of KIO3 used = molarity X volume (L)
= 0.02 mol/L X 0.001 L
= 0.00002 mol
1 mol of KIO3 reacts with 6 moles of S2O3-2
0.00002 mol of KIO3 reacts with 0.00012 moles of S2O3-2
moles of S2O3-2 used = 0.00012 mol
volume = 0.82 mL
1 mL = 0.001 L
0.82 mL = 0.00082 L
molarity of S2O3-2 = molarity / volume (L)
= 0.00012 mol / 0.00082 L
= 0.146 M
molarity of Na2S2O3 = 0.146 M
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