Question

When subjected to a force of compression, the length of a bone (compression Young's modulus 9.4 x 10⁹ N/m², tensile Young's modulus 1.6 x 10¹⁰ N/m²) decreases by 2.7 x 10^-5 m. When this same bone is subjected to a tensile force of the same magnitude, by how much does it stretch?Type your question here

Answer 1

Y=FL/(A*dL)

dL2/dL1=[(9.4*10^9)/(1.6*10^10)]

dL2==0.5875*2.7*10^-5=1.586*10^-5 m

Answer 2

Answer 3

change in length=stress*length/young modulus of elasticity here force applied is constant and initial length is also constant then dl1*yc1=dl2*Yt2 then dl=2.7*10^-5*9.4*10^9/1.6*10^10 dl=1.58625*10^-5m

Answer 4

( 2 ) When subjected to a force of compression , the length of a bone decreases by2.x 10-5.m . When this same bone is subjected to a tensile force of the same magnitude, by how much does it stretch? Given young's modulus for compression Y bone = 9.4 x 10°N/m2 For tension Y bone = 1.6 x 1010N/m²