Question

Consider the following reaction: Fe3O4(s) + 4H2(g) --heat--> 3Fe(s) + 4H2O(l) What mass (in g) of Fe3O4 is needed to consume 1.05 g of H2? Enter only the numeric value of your answer (no units).

Answer 1

Fezon (s) + 4H219) o, 3 Fecs) + 4H2010) weight of H₂ = 1.05g. no. of mole of M₂ = Weight 1.05g molar mass aglmal = 0.525 mol Acc. to w ea, 4 mol H₂ react with Imole fez On then, 0.525 mol H₂ react with tx 0.525 = 0.13125 mul Fego, he no. of mole of Fez by needed = 0.13125 mod.. mars Oy needed - modx Molarmas = 0.13125 mal x 231.5 gimos = 30.49 Hence, 30.4g of Fezon is needed to consume 1.05g of the (numeric value of answer without unit is 30.4. :)