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AS FOR
GIVEN DATA...
(b) Claim: Suppose that G is a graph on n 3 vertices in which the
degree of every vertex is exactly 2. Then G is a cycle. Proof. We
proceed by induction on n, the number of vertices in G. Our base
case is simple: for n 3, the only graph with 3 vertices in which
all vertices have degree 2 is C3, which is a cycle. For our
inductive step, we start by assuming that our claim is true for n.
That is: we assume if G is a graph on n vertices in which every
vertex has degree 2, then G is a cycle Using this, we want to prove
our claim for n +1: that is, we want to take any graph G on n1
vertices in which every vertex has degree 2, and show that G must
also be a cycle. Doing this is straightforward! Just take any edge
r, y E G, and perform edge contraction2 othis edge. The result is a
graph on n vertices, in which all vertices still have degree 2;
therefore, by our inductive assumption, this contracted graplh was
already a cycle Now, undo this contraction! This extends our graph
to a cycle that's longer by one edge. In particular, it means that
our original graph was a cycle, aธ desired.
EXPLANATION ::-
Performing an edge-contraction can result in a graph in which not all vertices have degree 2. For example the graph that comprises of 2 copies of C_3 (2 triangles).
Then performing edge contraction for 2 vertices belonging to same triangle results in a triangle and a copy of K_2 which is clearly not a cycle.
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Find the logical mistakes in these proofs, and explain why the mistakes you've identified cause problems in their a...
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