Question

i need help on just #3 (refer back to #1) thanks so much!

m, vim Vz 1) in the fume hood there is a 2.00 L bottle of a stock solution of dye that is 1.55 M. What volume of this dye in ml) should you place in a 100.0-ml volumetric flask in order to prepare a 0.30 M solution of dye? (2 pts) dan stort son diw bn sano Sa (r559 29 2.0) 0. 30 (100) = 19.4 mL Meno I.SS in no lo 2) What volume (in ml) of the stock dye (from previous problem) solution should be placed in a 500.0-ml flask in order to prepare a 0.40 M solution of the dye? (2 pts) 3 0103.4 T 3 088.Elbiupil baanbrons nobilio dizaino tom, v m2 armola tosi 91022 0,4 (S00 9 15w 129ml roming (2103) 55 tozalomojod holy 2 3) A person places 2.00 mL of the stock dye solution from problem number one in a 250.0-ml volumetric flask and fills it to the line. What is the concentration of the dye in this new solution? (2 pts) 1.5582.00) m = 15 250 V=2 1-0129 woninu o zaslom or su Vo?

Answer 1

3)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 1.55 M

V1 = 2 mL

V2 = 250 mL

use:

M1*V1 = M2*V2

M2 = (M1*V1)/V2

M2 = (1.55*2)/250

M2 = 0.0124 M

Answer: 0.0124 M