Question

1) In the fume hood there is a 2.00 L bottle of a stock solution of dye that is 1.55 M. What volume of this dye (in ml) should you place in a 100.0 mL volumetric flask in order to prepare a 0.30 M solution of dye? (2 pts) do 15 m l. S S (2) bl o u 0 1 - 10 snorenosion.3 0 10biano vg lo. 0.0103 m L 1 2) What volume (in ml) of the stock dye (from previous problem) solution should be placed in a 500.0 ml flask in order to prepare a 0.40 M solution of the dye? (2 pts) ,3.0103.4 30 .0103 llons to m, v=m, vz. mong or notworn

Answer 1

1)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 1.55 M

M2 = 0.3 M

V2 = 100 mL

use:

M1*V1 = M2*V2

V1 = (M2 * V2) / M1

V1 = (0.3*100)/1.55

V1 = 19.4 mL

Answer: 19.4 mL

2)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 1.55 M

M2 = 0.4 M

V2 = 500 mL

use:

M1*V1 = M2*V2

V1 = (M2 * V2) / M1

V1 = (0.4*500)/1.55

V1 = 129 mL

Answer: 129 mL