How do I go about making a solution for lab that is supposed to be "2 mmol of MgSO4 in 40 mL of DMF." The formula weight of Magnesium Sulfate is 120.366g. Would the stoich be (120.366g/1mol)*(0.002mol/1L)*(1L/1000mL)*(40mL) = 0.009629g which would result in me putting 0.009629g of MgSO4 in the vial and then adding the 40mL of DMF to it?
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Molar mass of MgSO4 is 120.366 g/mol
1 mol is equivalent to 120.366 g
Thus 1 mmol is equivalent to 120.366/1000 = 0.120366 g
Thus 2 mmol is equivalent to 2*0.120366 = 0.240732 g
Thus to make a solution " 2 mmol of MgSO4 in 40 mL of DMF" we need to add 0.240732 g MgSO4 should be taken in a vial and then add 40 mL of DMF.
How do I go about making a solution for lab that is supposed to be "2 mmol of MgSO4 in 40 mL of DMF." The formula weight...
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