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Calculate the solubility at 25 °C of AgBr in pure water and in 0.38 MK,S,O,. Youll probably find some useful data in the ALE
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Answer #1

(1) in pure water AS BY D — Astav) + Bi (as) -13 5. 35x 10 = Iss= [Agt ] [Br] 5.35x 103 52 S= 7.31x 167M solubility = 7.3 X

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