Question

USC e Reterences to access important values if needed for this question. The following information is given for tin at latm: T = 2270.00°C AHvap (2270.00°C) = 1.939 x 10 Jg T = 232.00°C AH fus (232.00°C) = 59.60 J/g Specific heat solid = 0.2260 J/g °C Specific heat liquid = 0.2430 J/g °C A 21.40 g sample of liquid tin at 522.00°C is poured into a mold and allowed to cool to 28.00°C. How many kJ of energy are released in this process? (Report the answer as a positive number.) Energy L k Submit Answer Retry Entire Group 2 more group attempts remaining

Answer 1

heat released(q) = m*s1*DT1 + n*DHfus + m*s2*DT2

m = mass of Sn liquid = 21.4 g

S1 = specific heat of Bi = 0.243 j/g.c

DT1 = (522-232) = 290

m = mass of Sn solid = 21.4 g

S2 = specific heat of sn = 0.2260 j/g.c

DT2 = (233-28) = 205

heat released(q) = 21.4*0.243*290+21.4*59.6+21.4*0.226*205

                 = 3.775 kj

answer: 3.78 kj