Question

Use the References to access important values if needed for this qu The following information is given for nickel at 1 atm: T = 2732.00°C AHvap (2732.00°C) = 6.450 x 108 J/g AHS (1453.00°C) = 300.1 J/g T = 1453.00°C Specific heat solid -0.4440 J/g °C Specific heat liquid = 0.7320 J/g °C A 31.50 g sample of solid nickel is initially at 1430.00°C. If 7.626 x 103 J of heat are added to the sample at constant pressure P=1 atm), which of the following is/are true? (Select all that apply.) The sample is a liquid. The sample is at a temperature greater than 1453.00°C. The sample is a solid in equilibrium with liquid. The sample is at a temperature of 1453.00°C. The sample is a solid. Submit Answer Retry Entire Group 8 more group attempts remaining

Answer 1

Heat absorbed by solid nickel, q = mc$\Delta$t

Where m is mass of the substance= 31.50 grams

c is specific heat of solid =0.4440 j/g oC

Change in temperature = t-1430

7626 = 31.50*0.4440*(t-1430)

t = 1975.25 Of

The obtained temperature is greater than fusion temperature of solid nickel.

Therefore, the sample is liquid and has a temperature greater than 1453.00 oC.