Homework Answers
Ti = 1387.0 oC
Tf = 1659.0 oC
here
Cs = 0.711 J/g.oC
Heat required to convert solid from 1387.0 oC to 1410.0 oC
Q1 = m*Cs*(Tf-Ti)
= 30.1 g * 0.711 J/g.oC *(1410-1387) oC
= 492.2253 J
Hf = 1653.0 J/g
Heat required to convert solid to liquid at 1410.0 oC
Q2 = m*Hf
= 30.1g *1653.0 J/g
= 49755.3 J
Cl = 0.908 J/g.oC
Heat required to convert liquid from 1410.0 oC to 1659.0
oC
Q3 = m*Cl*(Tf-Ti)
= 30.1 g * 0.908 J/g.oC *(1659-1410) oC
= 6805.3692 J
Total heat required = Q1 + Q2 + Q3
= 492.2253 J + 49755.3 J + 6805.3692 J
= 57053 J
= 57.053 KJ
Answer: 57.053 KJ
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