need solution 1. [5 marks] The proportion of lost packets Types I and II in a network are random variables X1 and X2...

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1. [5 marks] The proportion of lost packets Types I and II in a network are random variables X1 and X2 with the joint probabi

math Statistics-And-Probability

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Answer 1

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to tx, , X2 (X1g K2) = {x, +22, o rx <1? 05%2</ -otherwise Cov (X13X2) = E[X1 X2] - E[X1]E[x2] firstly we calculate - E[X, X2 St 서 7 2 꽃. - 유두 - 120 + 7 : + 2) | Ex) = {}(74 | = { cosx+35at in . V2 12 2 | [ ] as = Jst!! | CW (X9x2) =E[Xixo) - Fix] E[x

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need solution 1. [5 marks] The proportion of lost packets Types I and II in a network are random variables X1 and X2...

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need solution 1. [5 marks] The proportion of lost packets Types I and II in a network are random variables X1 and X2...

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Add Answer to: need solution 1. [5 marks] The proportion of lost packets Types I and II in a network are random variables X1 and X2...

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need solution 1. [5 marks] The proportion of lost packets Types I and II in a network are random variables X1 and X2...