Question

When 3.25 g of sodium hydroxide (NaOH) was dissolved in 100.00 g of water a value of 10.50^oC was obtained for ΔT.
Calculate the molarity of the sodium hydroxide solution.

Calculate the value (calories) for the heat of solution of 3.25 g of NaOH

Calculate the number of calories that would be produced if one mole of sodium hydroxide was dissolved. (ΔH_solnNaOH)

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Answer 1

112= most (memars of solution Csolute + solvent ) = 3:25+100.00 = 103.259 ) Z = 103.25 * 4:184x10150 F4535.98 J F 1084-125 Calories a) molarity of sodiumhydroxide solution molarity = melarmaus* vin ml mars e 1000 = 3.25 x 1000 40 . 103.25 = 0.787 M 3) moles of NaOH = mars = 3:25 + 0.08125 moles molarmais 0.08125 moles of Nach gives - 10840125 calories 1 mole of Naot gives -> IX 10846125 0.08125 3 13343 calories → 133x104 calories mol Ah soln of Nach = 1:33x10 " calories