Question

C. ΔH for Reaction of HCl_(aq) and NaOH_(s):
Volume of HCl: .05 L
Volume of water: .05 L
Volume total: .1 L
Molarity of HCl: 2.08 M
Mass of NaOH: 3.93 g
ΔT for reaction C: 19°C

1. Calculate the number of moles of NaOH

2. Using NaOH as the limiting reagent, calculate the molarity of the resulting sodium chloride solution.

3. Calculate the value (calories) for the heat of reaction.

4. Calculate the ΔH for this reaction.

5. Is the reaction exothermic?

	Water	Sodium Hydroxide	Sodium Chloride	Potassium Chloride
Conc. (M L^-1)		1	1	1
Density (g mL^-1)	1	1.04	1.04	1.10
Specific Heat (cal g^-1 C^-1)	1	.95	.94	.90

Given HCl concentration is after dilution

Answer 1

Vuliol Hel 30.052 Hol of water = o-osL Vitafels Oollit Malarity of Hel 52.08 M of luation. - Mole at HCl = MX V obter AN AH for reaction = 0.0988- 13.7 kcal & - 342 bal. Actuelt Naoh tha S. Bose Stangail Whenever S. Base & s. And rects +13.7 kead heat relased per eaivalent this is called as enthalpy of neutilizator So here - 13.7 keat is used to -2.087.1 = 0.208 Moss NaoH = 3.0384 Molat Naohs 3.93 = 0ogg to NaoH -0.098 Mol Naal than trich - 0.208ml O bygmo) Limiting reagent on Ath. Omol a 2018-mopose multibly. obove reaction is exothers in nature, because heat relosed. reaction ① Molnity of Nach 5 0.098 = 0.98M i sp heat of Hel regulad.