When 50.08 g of 1.00 M NaOH at 23 C is added to 50.22 g of...
When 50.08 g of 1.00 M NaOH at 23 C is added to 50.22 g of 1.00 M HCl at 23 C, the resulting temperature of the mixture is 29.7 C. (Assume that the calorimeter constant is equal to zero. Assume that the solutions have the same specific heat capacity (4.184 J/g·K) and density (1.00 g/mL) as water. Take care with signs.)
a) What is ΔT for this process?
b) Calculate qsolution (in J) for this process.
c) Calculate qreaction (in J) for this process
d) Calculate the moles of NaOH and the moles of HCl used in the reaction. Determine whether NaOH or HCl is the limiting reactant.
e) What is the enthalpy change (ΔHrxn, in kJ/mol) for this process per mol of the limiting reactant?
f) Is the reaction of NaOH with HCl an endothermic or exothermic process?
Homework Answers
Page 36 When 50.0 mL of 1.00 M HCI(aq) and 50.0 mL of 1.00 M NaOH(aq),...
Page 36 When 50.0 mL of 1.00 M HCI(aq) and 50.0 mL of 1.00 M NaOH(aq), both at 22.0 °C, are added to a coffee cup calorimeter, the temperature of the mixture reaches a maximum of 28.9 C. What is the approximate amount of heat produced by this reaction? Specific heat of water is 4.184 J/g C HCl(aq) + NaOH(aq) → Nacl(aq) + H2O() The heat given off by the reaction is equal to that taken in by the solution....
Data Collection Table for Part C (This information needs to be in your lab notebook before you come to lab. You will fi...
Data Collection Table for Part C (This information needs to be in your lab notebook before you come to lab. You will fill in the data directly into your notebook as you complete the lab.) 24.2 23.7 30.4 6.45 Initial Temp. of HCI Initial Temp. of NaOH Final Temp. of Mixture AT solution solution qreaction Number of moles of water formed AHrxn (reaction / moles water) (units: kJ/mol) Calculate AT solution, (average the initial temperatures of HCl and NaOH as...
C. ΔH for Reaction of HCl(aq) and NaOH(s): Volume of HCl: 0.055 L Volume of water:...
C. ΔH for Reaction of HCl(aq) and NaOH(s): Volume of HCl: 0.055 L Volume of water: 0.045 L Volume total: 0.1 L Molarity of HCl: 2.08 M Mass of NaOH: 4 g ΔT for reaction C: 23°C number of moles of NaOH : 0.100 moles molarity of the resulting sodium chloride solution : 1.00 M ΔT : 23.0 °C Calculate the value (calories) for the heat of reaction. Calculate the ΔH for this reaction.
When 50.0 mL of 1.00 M HCl and 50.0 mL of 1.00 M NaOH are mixed...
When 50.0 mL of 1.00 M HCl and 50.0 mL of 1.00 M NaOH are mixed in a constant-pressure calorimeter, the temperature of the solution increases from 21.0°C to 27.5°C. Calculate the enthalpy change of the reaction per mole of HCl assuming the solution has a total volume of 100.0 mL and a density of 1.000 g/mL. The specific heat of water is 4.184 J/q°C Asoln = 2720
B. ENTHALPY OF NEUTRALIZATION NaOH temp. 29 HCl temp.: 22.0 Average temp. T: 22.06 Time Temp...
B. ENTHALPY OF NEUTRALIZATION NaOH temp. 29 HCl temp.: 22.0 Average temp. T: 22.06 Time Temp 0:30 29.7 Calorimeter mass: 3.872 200 29.7 Calorimeter + HCl mass: 54.5292 130 129.7 2:00 226 Calorimeter + HCI + NaOH mass: 105.174 2.30 22.629.7 3:00 295 3:30 225 4:00224 4:30 29.4 295. 5:00 29.3 29.4 ]296 129.3 22.0 Final pH: 2 0:30 -1:00 1:30 14:00 15:00 4:30 8 8 Calculations: Moles NaOH: Moles HCI: Limiting Reagent: Calculated molar enthalpy of neutralization: kJ/mol Literature...
C. ΔH for Reaction of HCl(aq) and NaOH(s): Volume of HCl: .05 L Volume of water:...
C. ΔH for Reaction of HCl(aq) and NaOH(s): Volume of HCl: .05 L Volume of water: .05 L Volume total: .1 L Molarity of HCl: 2.08 M Mass of NaOH: 3.93 g ΔT for reaction C: 19°C 1. Calculate the number of moles of NaOH 2. Using NaOH as the limiting reagent, calculate the molarity of the resulting sodium chloride solution. 3. Calculate the value (calories) for the heat of reaction. 4. Calculate the ΔH for this reaction. 5. Is...
.237g of NaOH(s) is added to 2 moles of liquid water in a constant pressure calorimeter....
.237g of NaOH(s) is added to 2 moles of liquid water in a constant pressure calorimeter. The water in the calorimeter increases from 25 degrees Celcius to 43.2 degrees Celsius. What is the q of the reaction? Water has a specific heat capacity of 4.184 J/g degrees Celsius. Is this reaction exothermic or endothermic?
The reaction of an acid such as HCl with a base, such as NaOH, in water...
The reaction of an acid such as HCl with a base, such as NaOH, in water is an exothermic reaction. HCl(aq) + NaOH(aq) ---> NaCl(aq) + H2O In one experiment, a student placed 55.0 mL of 1.00 M HCl in a coffee-cup calorimeter and carefully measured its temperature to be 35.5oC. To this was added 55.0 mL of 1.00 M NaOH solution whose temperature was also 35.5oC. The mixture was quickly stirred, and the student noticed that the temperature of...
when .0015 M of HCl reacts with .0035 M NaOH. how do I get HCl as...
when .0015 M of HCl reacts with .0035 M NaOH.
how do I get HCl as the limiting reactant?
HC # Results/Observations 1 Reaction Between Hydrochloric Acid and Sodium Hydroxide Table 1 ml LOM mol HCI ml 1.0M mol NaOH Temperature NaOHT change. "C 19. 10 0045 50L2012 .0005 22.4 #2 19.10.0 .004 10.09.11 .001 24.3 #3 1949350 -0035 15.020 Ốc DD15 265 #499 300 003 20.0 20.10 .002 27.3 #5 A5 2.0 .0025 25.0 20. 0 0025 2100 #6...
Calorimetry 1. Consider the following data: 4.99 g g 50 g 24 C 38.7 °C 111.1...
Calorimetry 1. Consider the following data: 4.99 g g 50 g 24 C 38.7 °C 111.1 g/mol Mass of CaCl Mass of Water Intial Temperature Final Temeprature Molar Mass of CaCl2 (a) Calculate the heat of solution. (AH) Assume that the specific heat of the solution is the same as water, 4.184 J/g- C and that no heat is gained or lost by the cup. (4 pts) (b) Calculate the number of moles of CaCl2. (3 pts) (c) Calculate the...
Page 36 When 50.0 mL of 1.00 M HCI(aq) and 50.0 mL of 1.00 M NaOH(aq), both at 22.0 °C, are added to a coffee cup calorimeter, the temperature of the mixture reaches a maximum of 28.9 C. What is the approximate amount of heat produced by this reaction? Specific heat of water is 4.184 J/g C HCl(aq) + NaOH(aq) → Nacl(aq) + H2O() The heat given off by the reaction is equal to that taken in by the solution....
Data Collection Table for Part C (This information needs to be in your lab notebook before you come to lab. You will fill in the data directly into your notebook as you complete the lab.) 24.2 23.7 30.4 6.45 Initial Temp. of HCI Initial Temp. of NaOH Final Temp. of Mixture AT solution solution qreaction Number of moles of water formed AHrxn (reaction / moles water) (units: kJ/mol) Calculate AT solution, (average the initial temperatures of HCl and NaOH as...
When 50.0 mL of 1.00 M HCl and 50.0 mL of 1.00 M NaOH are mixed in a constant-pressure calorimeter, the temperature of the solution increases from 21.0°C to 27.5°C. Calculate the enthalpy change of the reaction per mole of HCl assuming the solution has a total volume of 100.0 mL and a density of 1.000 g/mL. The specific heat of water is 4.184 J/q°C Asoln = 2720
B. ENTHALPY OF NEUTRALIZATION NaOH temp. 29 HCl temp.: 22.0 Average temp. T: 22.06 Time Temp 0:30 29.7 Calorimeter mass: 3.872 200 29.7 Calorimeter + HCl mass: 54.5292 130 129.7 2:00 226 Calorimeter + HCI + NaOH mass: 105.174 2.30 22.629.7 3:00 295 3:30 225 4:00224 4:30 29.4 295. 5:00 29.3 29.4 ]296 129.3 22.0 Final pH: 2 0:30 -1:00 1:30 14:00 15:00 4:30 8 8 Calculations: Moles NaOH: Moles HCI: Limiting Reagent: Calculated molar enthalpy of neutralization: kJ/mol Literature...
when .0015 M of HCl reacts with .0035 M NaOH.
how do I get HCl as the limiting reactant?
HC # Results/Observations 1 Reaction Between Hydrochloric Acid and Sodium Hydroxide Table 1 ml LOM mol HCI ml 1.0M mol NaOH Temperature NaOHT change. "C 19. 10 0045 50L2012 .0005 22.4 #2 19.10.0 .004 10.09.11 .001 24.3 #3 1949350 -0035 15.020 Ốc DD15 265 #499 300 003 20.0 20.10 .002 27.3 #5 A5 2.0 .0025 25.0 20. 0 0025 2100 #6...
Calorimetry 1. Consider the following data: 4.99 g g 50 g 24 C 38.7 °C 111.1 g/mol Mass of CaCl Mass of Water Intial Temperature Final Temeprature Molar Mass of CaCl2 (a) Calculate the heat of solution. (AH) Assume that the specific heat of the solution is the same as water, 4.184 J/g- C and that no heat is gained or lost by the cup. (4 pts) (b) Calculate the number of moles of CaCl2. (3 pts) (c) Calculate the...
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