Given that US concentration = 6 mg/L
Molecular weight of solute= 243 g/mol
One litre of drug consists of 6 mg of solute ie 0.006 g
Number of moles = 0.006 g/(243 g/mol)
= 2.469×10-5 moles
10-6 mole = 1 micromole (mcmol)
2.469 ×10-5 moles = ? micromoles
= 2.469×10-5/10-6 micromoles(mcmol)
= 24.69 micromoles (mcmol)
Therefore 6 mg/L = 24.69 mcmol/L
B)
Given that US concentration = 38 mg/L
Molecular weight of solute= 114 g/mol
One litre of drug consists of 38 mg of solute ie 0.038 g
Number of moles = 0.038 g/(114 g/mol)
= 3.333×10-4 moles
10-6 mole = 1 micromole (mcmol)
3.333 ×10-4 moles = ? micromoles
= 3.333×10-4/10-6 micromoles(mcmol)
= 333.3 micromoles (mcmol)
Therefore 38 mg/L = 333.3 mcmol/L
C)
please solve and explain Please calculate the therapeutic concentration in Sl units for Drug X, the US concentration...
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