Question

(3 pts.) 3 13.0 moles of potassium react with excess oxygen, how many moles of potassium oxide will form? K(s) + _ _02 (g) → K20 (5) (3 pts.) 4 How many grams of potassium oxide can be produced from 4.50 g of K and an excess of O, based on the equation in question 3?

Answer 1

24 + 1/2, ko YK+ + 2 ko. let & be the number of moles of to Produced by 3 moles of 'k' 4 moles of k' gives - 2 moles of to 3 moles of ll gives - x Cross multiply 4x = 2X 3 x= 1.5 holes of ko Let cyl be the mass of ko produced by 4.50 g of ki 4 X 39 g of 'k' givu → 2X argot ko. 4.509 of k gives - lyi Cross multiply 4X39x9 = 2x 94 x 4.50 ya 5.47309.