1 U12 PUILLS PIEVIUUS RUISVEISTILLIICIIa u.UUU. LV VIY IVULCST ASR Tuul Tlalnel Al(s) + O2(g) → Al2O3(s) (a) Consider t...
How many grams of Al2O3 are produced when 38.9 grams of O2 react completely with Al? 4 Al (s) + 3 O2 (g) → 2 Al2O3 (s)
Aluminum oxide (Al2O3) is produced according to the following equation. 4 Al(s) + 3 O2(g) → 2 Al2O3(s) If the reaction occurs with an 82.4% yield, what mass of aluminum should be reacted with excess oxygen to produce 45.0 grams of Al2O3? a. 54.6 g Al b. 37.9 g Al c. 35.1 g Al d. 23.8 g Al e. 28.9 g Al How do we solve this problem
4. Consider the reaction of aluminum and oxygen: Al(s) + O2(g) Al2O3(s) (i). Which is the limiting reactant if we start with 30.0 g Al and 30.0 g O2? (ii). What is the Theoretical Yield for the reaction? (iii). If 25.85 g of Al2O3 was collected at the completion of the reaction (actual yield), what is the % yield for the reaction? 5. (a). A 1.506-g sample of limestone-containing material gave 0.558 g of...
Given the unbalanced reaction of Al(s) + O2 (g) ---> Al2O3 (s), determine which reagent, and how much will be left over after the reaction of 5.0 mol of Al (s) with 4.0 mol of O2 (g).
1. Balance the following reaction: Al(s) + F2 ---> AlF3 How many grams of aluminum fluoride would be produced from 40.84 g of aluminum (use the balanced equation above)? The molar masses are: Al, 26.981; F, 18.998, g per mole, respectively. Leave the answer as a fraction but state how many significant figures it has. (PS: Please show all the works! Thank you!)
1. Aluminum reacts with oxygen according to the following reaction: 4 Al(s) + 3 O2(g) -> 2 Al2O3 If 8.00 moles of oxygen are reacted with 8.00 moles of aluminum to completion, which is the excess reactant?
X 1. Aluminum reacts with oxygen to produce aluminum oxide 4 Al(s) + 3 O2(g) + 2 Al2O3(s) IF 3.0 moles of Alreact with excess O2, how many moles of AlzO3 can be formed? a) 1.0 mol b) 1.50 mol c) 3.0 mol d ) 4.0 mol e) 4.5 mol 10. What is the log of 5,400.05? a) 3.07 b) 3.37 c) 3.73 d) 37.32 e) 37.23 Short Answer Questions (True or False)
Oxygen gas reacts with powdered aluminum according to the following reaction: 4Al(s)+3O2(g)?2Al2O3(s). What volume of O2 gas, measured at 793 mmHg and 28 ?C, is required to completely react with 53.5 g of Al? Express the volume in liters to three significant figures.
1. When 15.4 g of aluminum (26.98 g/mol) reacts with 14.8 g of oxygen gas (32.00 g/mol), what is the maximum mass (in grams) of aluminum oxide (101.96 g/mol) that can be produced? 4 Al(s) + 3 O2(g) → 2 Al2O3(s) 2. If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion? Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O...
The thermochemical equation for the reaction is shown below: 4 Al(s) + 3 O2(g) → 2 Al2O3(s) AH = -3352 kJ How much heat is released when 12.1 g of Al react with O2(g) at 25 °C and 1 atm? 0 - 104 kJ 0 -3.59 x 105 kJ -1.50 x 103 kJ O-376 kJ A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction...