1. Aluminum reacts with oxygen according to the following reaction: 4 Al(s) + 3 O2(g) ->...
Aluminum oxide (Al2O3) is produced according to the following equation. 4 Al(s) + 3 O2(g) → 2 Al2O3(s) If the reaction occurs with an 82.4% yield, what mass of aluminum should be reacted with excess oxygen to produce 45.0 grams of Al2O3? a. 54.6 g Al b. 37.9 g Al c. 35.1 g Al d. 23.8 g Al e. 28.9 g Al How do we solve this problem
X 1. Aluminum reacts with oxygen to produce aluminum oxide 4 Al(s) + 3 O2(g) + 2 Al2O3(s) IF 3.0 moles of Alreact with excess O2, how many moles of AlzO3 can be formed? a) 1.0 mol b) 1.50 mol c) 3.0 mol d ) 4.0 mol e) 4.5 mol 10. What is the log of 5,400.05? a) 3.07 b) 3.37 c) 3.73 d) 37.32 e) 37.23 Short Answer Questions (True or False)
1. When 15.4 g of aluminum (26.98 g/mol) reacts with 14.8 g of oxygen gas (32.00 g/mol), what is the maximum mass (in grams) of aluminum oxide (101.96 g/mol) that can be produced? 4 Al(s) + 3 O2(g) → 2 Al2O3(s) 2. If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion? Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O...
Marked out of 1.00 Aluminum reacts with oxygen to form aluminum oxide according to the following unbalanced equation: Al(s) + O2 (g) → Al2O3 (s) If 5.0 moles of A react with excess oxygen, how many moles of Al2O3 can be produced? Select one: a. 1.0 mole b. 2.0 mole c. 3.0 mole d. 2.5 mole e. 10.0 mole Clear my choice Question 11 Not yet answered
4. Consider the reaction of aluminum and oxygen: Al(s) + O2(g) Al2O3(s) (i). Which is the limiting reactant if we start with 30.0 g Al and 30.0 g O2? (ii). What is the Theoretical Yield for the reaction? (iii). If 25.85 g of Al2O3 was collected at the completion of the reaction (actual yield), what is the % yield for the reaction? 5. (a). A 1.506-g sample of limestone-containing material gave 0.558 g of...
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 775 Torr and 23 ∘C , completely reacts with 52.1 g of Al?
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 782 Torr and 29 ∘C , completely reacts with 52.6 g of Al? (in L)
Oxygen gas reacts with powdered aluminum according to the following reaction: 4Al(s)+3O2(g)?2Al2O3(s). What volume of O2 gas, measured at 793 mmHg and 28 ?C, is required to completely react with 53.5 g of Al? Express the volume in liters to three significant figures.
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 774 Torr and 29 ∘C , completely reacts with 52.0 g of Al? (answer in Litres)
Aluminum oxidizes according to the following equation: 4 Al + 3 O2 -> 2 AL2 O3. If 0.048 mol of Al is placed into a container with 0.030 mol O2, what are the limiting and excess reactants? Based on the previous question, how many moles of excess reactant remain?