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A 33.21 g sample of a substance is initially at 23.2 °C. After absorbing 1787 J of heat, the temperature of the substance is
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Answer #1

m=13.21 g ÁT = (158.6–23.2)°c DT= 135.4°C heat=9= 17875 c = ? q=MCAT 1787 = 13-21 XCX 135-4 (31.00

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