Determine the mass of Na2SO3 necessary to prepare 250.0 mL of a solution that is 0.463 M Na2SO3
Determine the mass of Na2SO3 necessary to prepare 250.0 mL of a solution that is 0.463 M Na2SO3
Homework Answers
volume , V = 2.5*10^2 mL
= 0.25 L
use:
number of mol,
n = Molarity * Volume
= 0.463*0.25
= 0.1158 mol
Molar mass of Na2SO3,
MM = 2*MM(Na) + 1*MM(S) + 3*MM(O)
= 2*22.99 + 1*32.07 + 3*16.0
= 126.05 g/mol
use:
mass of Na2SO3,
m = number of mol * molar mass
= 0.1158 mol * 1.26*10^2 g/mol
= 14.59 g
Answer: 14.6 g
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