Question

III. (12 pts) Give name: C a.

Answer 1

Answer :

III.

Numbering is such that - ₂) Double bond gets the lowest numbers. ii) Double bond get. number (correr numbering) : priority over halogen i Numbering of the substituent is such that they their number is as low as possible, Keeping the li) and (ii) x (wrong numbering) intact. » As el get higher priority than a bond (Rule ) x (wrong numbering) → As the numbering of substituentis ... not as low as possible. 50, correct name is - :3-chloro-d-ethyleyelo hexa-1-ene, or, 3-chloro-d-ethyleyetohexene.

i) longest carbon chain incleeding the double bond. (7- carbon chain) 11) Numbering is such that double bond . get the number as low as possible. ii) Substituents are written in alphabe fically. 5o, Name of the compound- 2-chloro - 3-ethyl hepta-d-ene or al-chloro- 3-ethyl-d-heptene. By : Here, there is a sterreo centre. So we have to include its absolute configuration in the name

To determine the absolute configuration we have to specify the priority of the 4-substituents of o the chiral - centre. Br gets highest priority as its atimie man is highest. Then the long chain substituent is and priority. Then - Methy! is the 3rd priority. Then. His least . priority. How the movement from, + @ -> ☺ is = clockwise... Belt here least priority group (4) 7.. H is above the plane.. so the absolute com figura tiom is. ☺ Now we have to number the longest carbon chain for. IUPAC Mame.

double bond get priority over the halogen. (IUPAC rule). 5o, IUPAC name of the compound is — (58) - 5- bromo hexa-1-ene.

(Answered)