Why is 4+ for Uranium and 2+ for Vanadium correct? IX. Consider the following reduction half reactions written in alpha...

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Question

IX. Consider the following reduction half reactions written in alphabetical order involving Thallium (TI); Uranium (U); and V

Why is 4+ for Uranium and 2+ for Vanadium correct?

Answer 1

Answer #1

Here, you need to consider the one-electron oxidation/reduction process because the TlNO₃ solution will allow for only one electron- transfer.

According to the given data, there are two one electron-transfer processes: U⁴⁺/U³⁺ and V³⁺/V²⁺

Here, the reduction potential of V³⁺/V²⁺ is more than that of U⁴⁺/U³⁺.

As a result, U3+ undergoes oxidation to form U⁴⁺, whereas V³⁺ undergoes reduction to V²⁺.

Answer 2

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