Resolving the given forces into components
In x - direction
- F1 * cos 60 + F3 * cos 30 = 0 --------------- (1)
In y - direction
F1 * sin 60 - F2 - F3 * sin 30 = 0 -------------- (2)
from (1) , we have
F1 = 1.732 * F3
put this in (2)
1.732 * F3 - F2 - F3 * sin 30 = 0
put in the known values
1.732 * F3 - 5 - F3 * sin 30 = 0
1.232 * F3 - 5 = 0
F3 = 4.058 kips
and
F1 = 7.029 kips
TheLEN NO. GvEI-THREE FORES ARE IN EAUIIARIU TertmUNINS PND F BY THE HETHD OF REINCU ToTmENTS eon CurcNENT FORCES C...
or - NAME OF STUDENT - Saeed Rasool TOMEH 10./ 6WEU - THOCE FORCES ARE IN EOVILIBU DETERMINS AND F, By THE METHOD OF RECTANGULAR TV1PONENT Con CUTRENT FTES) CO-PLADER SAMT 52-5K/PS САН ТОА * FX tan60°=FX -skips FX = (tan 60°) (-5 kips) = -8.66 Kips v2 = 10 KPS:F3
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Express the magnitudes of the forces in pounds to three
significant figures. Separate your answers with commas.
Part B - The Sense of the Forces
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Complete each sentenc
e by dragging the appropriate word into the blank. The words can
be used more than once....