1) Enthalpy change = - 890.4 KJ
2) Enthalpy change = - 1335.6 KJ
3) Enthalpy change = - 445.2 KJ
CH_(g) + 2O2(g) → CO2(g)+ 2H2O(1) AH = -890.4 kJ When 1 mole of CO2(g) is produced, what is the enthalpy change? Wh...
AU for the reaction CH4 (8) + 2O2(g) - CO2(8) + 2H2O(l) in kJ at 298 K is AH(CH,) =-74.6kJ / mol AH (0) = -393.5kJ / mol AH,(4,0) =-285.8kJ / mol 1 A. -885.5 kJ B.668 kJ C. 885.5 kJ D.-668 kJ
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
Calculate the approximate enthalpy change, ?Hrxn, for the combustion of one mole of methane a shown in the balanced chemical equation: CH4+2O2?2H2O+CO2 Use the values you calculated in Parts A, B, C, and D, keeping in mind the stoichiometric coefficients. delta H CH4=1656 kJ/mol delta H O2=498 kJ/mol delta H H2O=-928 kJ/mol delta H CO2=-1598 kJ/mol
Calculate ∆Gº for the reaction, CH4(g)+2O2(g)→CO2(g)+2H2O(g), where ∆Gfº=-50.8 kJ/mol for CH4(g), -394 kJ/mol for CO2(g), and -229 kJ/mol for H2O(g).
Calculate ∆Gº for the reaction, CH4(g)+2O2(g)→CO2(g)+2H2O(g), where ∆Gfº=-50.8 kJ/mol for CH4(g), -394 kJ/mol for CO2(g), and -229 kJ/mol for H2O(g): 572 kJ -801 kJ -572 kJ 801 kJ
CH4(g) + 2O2(g), AH° = 803 kJ which of the following For the following reaction, CO2(g) + 2H2O(g) = will increase K? Select one: O a. increase the temperature of system O b. none of the above O c. decrease number of moles of methane O d. all of the above O e increase volume of system
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
1. The standard enthalpy change for the combustion of mole of propane is -2043.0 kJ. CH_(g) +5 0 (g) →3002(g) + 4H2O(g) Calculate Hº for propane based on the following standard molar enthalpies of formation. molecule CO (9) H2O(g) AH (kJ/mol-rxn) -393.5 -241.8 a. +1407.7 kJ/mol-rxn b. +104.7 kJ/mol-rxn c.-104.7 kJ/mol-rxn d -4190.7 kJ/mol-rxn e. -1407.7 kJ/mol-rxn 2. Which of the following statements is/are CORRECT? 1. If a reaction occurs at constant pressure, 4-AH. 2. The change in energy for...
Using average bond enthalpies (linked above), estimate the enthalpy change for the following reaction: CH_(g) + 2O2(g) CO2(g) + 2H2O(g)
Part E Calculate the approximate enthalpy change , ?H?, for the combustion of methane: CH4+2O2?2H2O+CO2 Use the values you calculated in Parts A to D, keeping in mind the stoichiometric coefficients. Please explain.