Question

Please see the Lab 9 Pre-Lab Tutorial on the Canvas page for CHM 210 Lab for a more detailed explanation of the concepts in pre-lab question 3. 3. Consider the two gas-collection apparatuses pictured below. In each case, as is trapped in the upper part of the inverted us-collection tube and water fills the lower part of the tube. keeping the gas sealed inside the tube. a. Identify which apparatus pictured below shows a trapped gas sample with pressure greater than atmospheric pressure and which shows a trapped gas sample with pres- sure less than atmospheric pressure. Then briefly explain how (and why you can tell whether the pressure of the trapped gas is greater than or less than atmospheric pres sure. b. Given that atmospheric pressure is 755.3 mm Hg, calculate the total gas pressure inside the tube pictured at right, with the water level inside the tube 15.3 cm above the surrounding water LLLLLLLLLLLLL BOLDUDDUULUUUUUUUUUUUU c. Given that atmospheric pressure is 755.3 mm Hg, calculate the total gas pressure inside the tube pictured at right, with the water level inside the tube 7.5 cm below the surrounding water TEMPERATURE PRESSURE (atm) 1.05 76,1 Pre-lab extra You can save yourself some time in lab by graphing these P vs. T data in Excel before lab. Follow the directions in Part 2. steps 10-11 of the procedure. Bring the Excel file to lab and you will be able to insert your own data and finish the graph in a couple minutes. 1.991 0.951 0.896 0.345 120 CHM 210 - Lab 9 0.771

Answer 1

0 @ Abbaratus pictured in@ shows a trapped gas sample with pressuré greater than atmospheric pressure and picture @ shows a trapped gas with pressure less than atmospheric pressure. The level of Hg column in the gas cylinder in figure © is lower than the level of Hg in the beakers which is open to atmosphere and en Lequilibrium with atmospheric pressure Similarly, the level of Hg in the gas cylinder in figure is above the level of Ag in the beaker. This indicates the aas is less than the atmospheric pressure. pressure of gas é's less of Pgas + h = Patin Th=15.3 cm of Hg or Pgas +153 mm of ttg = 755.3 mm Hg In or Pgas = (755.3-153) mm Hg = 602.3 mm Hg (Ans) ① Pgas + h = Patin or Pgas – 75 mm Hg = 755.3 mmng Th=-7.5 cu = - 75 mm) or Paas = (755.3+75) mm Hg = 830.3 mm Hg (Ans) =153 mm