a) Find the percentage by mass of I in CaI2 if it is
13.6% Ca by mass. *Round your answer to one decimal place.
_________%
b) Find the percentage by mass of oxygen (O) in N2O4
if it is 30.4% nitrogen (N) by mass.
______%
(a) percentage by mass of I in CaI2 = 86.4 %
(b) percentage by mass of O in N2O4 = 69.6 %
Explanation
(a) Given : percentage by mass of Ca in CaI2 = 13.6 %
percentage by mass of I in CaI2 = (total percent) - (percentage by mass of Ca in CaI2)
percentage by mass of I in CaI2 = (100 %) - (13.6 %)
percentage by mass of I in CaI2 = 86.4 %
(b) Given : percentage by mass of N in N2O4 = 30.4 %
percentage by mass of O in N2O4 = (total percent) - (percentage by mass of N in N2O4)
percentage by mass of O in N2O4 = (100 %) - (30.4 %)
percentage by mass of O in N2O4 = 69.6 %
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