Question

Complete each of the following half-reactions with the correct number of electrons and then arrange them from strongest oxidizing potential to strongest reducing potential. Strongest Oxidizing Potential Drag the text blocks below into their correct order. 2e 12(s) + → 21 (aq) E° = +0.53 V 4e Fe (aq) + → Fez (aq) E° = +0.77 V F2(g) + 2F-(aq) E° = +2.87 V AHOROD WWWWWWWWWWWWWWWWWWWWWWWWWWWWWWY Au3+ (aq) + Au(s) E° = +1.50 V 2H'(aq) + - + H2(g) E° = +0.00 V 5e Cu2+ (aq) + → Cut(aq) E = +0.15 V Strongest Reducing Potential

Answer 1

The compound which have lowest standard reduction potential show strongest reducing property while the compound which have highest standard reduction potential show strongest oxidizing property F is the strongest oxidizing agent 21 (aq) E +0.53 V 2(s) 2e Fe3 (aq) Fe2 (aq) E = +0.77 V е- 2F(aq) E+2. 87 V F2(g) 2e Au(s) E+1.50 V Au3- (aq) + 3е- 2e 2H'(aq) H2(g) E +0.00 V Cu2 (aq) Cu'(aq) E = +0.15 V Strongest to lowest oxidizing agent F Au3+>Fe3+>12> Cut > H+ lowest to strongest reducing agent highest reducing agent is H+