Question

2. Saccharin is a common artificial sweetener without calories. When 3.00 g of the sodium salt of saccharin (the anion of saccharin with a Na cation) is dissolved in 50.0 mL of water, it takes 14.6 mL of 1.00 M HCl to reach the equivalence point. Using the data provided, calculate the molecular weight of sodium saccharin?

Answer 1

Since it is a sodium salt,

number of moles of HCl = number of moles of sodium saccharin

Number of moles of HCl = M*V = 1.00 M * 14.6 mL = 14.6 mmol = 0.0146 mol

Number of moles of sodium saccharin = moles of HCl = 0.0146 mol

Mass of sodium saccharin = 3.00 g

Molecular weight of sodium saccharin = mass/moles = 3.00 g / 0.0146 mol = 205.4795 g/mol

Molecular weight of Sodium saccharin = 205.48 g/mol