Question

Complete the Lewis structure of the compound shown below and indicate which of the following statements are true. 46 Η Η H C =C-C-N H=21日 An sp2 hybrid orbital on C-1 overlaps with an sp hybrid orbital on C-2 to form the sigma bond between C-1 and C-2. There are ten o bonds in this molecule. There are five i bonds in this molecule. The C-2 and C-3 atoms cannot rotate about the internuclear axis between the two atoms since the 1 bonds would break. The C-N bond is formed from overlap of an sp3 hybrid orbital from the carbon atom with an sp2 hybrid orbital from the nitrogen atom. There are three lone pairs of electrons in the complete Lewis structure. The 7 bonds between C-2 and C-3 are formed by overlap of unhybridized p atomic orbitals.

Answer 1

:0 3- H - C - CEC-Ć - N - H (1) (2) G has 12 hybridization. False. ( o st) to s' bonds - True five 'r' bonds - false (3 k bonds) (-2 & (-3 Cannot rotate - True. C-N cis sp3 f N is also sp . So given Statement is false 2 lone bar of é on o f t è bain on 'N' - This totale = 2+1=3 lon pain of é - True. ñ bonds form b/w G2 f C-3 atomic orbitals. is due to Unhybridized b

Last statement(7) is true.