Triple equality ( ) is used to equivalency or showing two substances equivalent. It used for molar mass calculations.
Ca3(PO4)2 : The metal cation is Ca2+ and anion formula is PO43-
We Used value of the anion charge as the subscript for the cation and use the value of the cation charge as the subscript for the anion : to get compound formula is Ca3(PO4)2.
so, can write Triple equality ( ) for Ca3(PO4)2 :
3 Ca2+ 2 PO43-
or alternatively 1 mol of Ca3(PO4)2 3 moles of Ca2+
1 mol of Ca3(PO4)2 2 moles of PO43-
what is the ksp expression for a solution of Ca3(PO4)2?
Calculate the solubility of Ca3(PO4)2 in a solution containing 0.0539 M Na3PO4. Ksp=2.0*10^-29 for Ca3(PO4)2
In a purely competitive market, there is a triple equality. What is it? The triple equality can be broken up into two equations that each signify a difference efficiency. What are these efficiencies? Why are they important?
Which of the following compounds will be soluble in water: NaNO3, Ca3(PO4)2, CuCl2, and Fe2S3? Ca3(POa)2 and Fe2S3 CuCl2 and Fe2S3 NANO3, Ca3(PO4a)2, and Fe2S3 NaNO3 and CuCl2 and Ca3(PO4)2 ONaNO3
the crc handbook gives the solubility of ca3(po4)2 at 25 c as .0012g/100ml . determine the molar solubility of ca3(po4)2 . this is the molarity of saturated solution . and determine ksp of ca3(po4)2
Question 24 1 pts Write the solubility product constant expression for calcium phosphate, Ca3(PO4)2 O [Ca2+][PO43-M[Ca3(PO4)2] O Ca2+1*[PO43-12 O [Ca2+][PO43-1 O [Ca2+12[PO43-13
---Percent yield of Ca3(PO4)2 from CaCL2 Mass of beaker + CaCL2 = 342.231g, Mass of beaker = 341.852g, Mass of filter paper + Ca3(PO4)2 ppt = 0.726, Mass of filter paper = 0.506 1. Show the calculation for theoretical yield of Ca3(PO4)2 2. Show the calculation for percent yield of Ca3(PO4)2
The Ksp of Ca3(PO4)2 is 1x 10-33. What is the solubility in moles per liter (mol/L) of Ca3(PO4)2 (s) in a 0.01 M Ca(NO3)2 (aq) solution? (Note: The molar mass of Ca3(PO4)2 is not needed in this problem, which asks for moles per L.) a. 3.2 x 10-14 mol/L b.3.0 x 10-15 mol/L c. 9.8 x 10 mol/L d. 1.6 x 10-14 mol/L e. 5.0 x 10-32 mol/L
Which of the following compounds will be soluble in water: NaNO3, Ca3(PO4)2, CuCl2, and Fe,S3? NaNO3. Ca3(PO4)2, and Fe253 CuCl2 and Fe253 NaNO3 and CuCl2 Caz(PO4)2 and Fe 253 NaNO3 and Caz(PO4)2 Next →
What is the solubility of Ca3(PO4)2 (s) in mg/L, in a solution buffered at pH 7.2 using a phosphate buffer such that TOTPO4 = 10-2M?