(20 pts) Use Thevenin's theorem to find Vo in the circuit. 6 V 2 k2 2 I Ik() 1 k12 0 (20 pts) Use Thevenin&...
Use Thevenin's theorem to find voin the given circuit where V = 9 V. 2Α 6Ω 5Ω 4 Ω + % V 3 Ω 12 Ω 19V The value of vo in the given circuit is mV.
3. Find V, from following circuit using Thevenin's theorem. 3 kΩ 6 kΩ 3 kΩ ' 4 mA 12V 12V 4. Find Vo from following circuit using Norton's theorem only. 12V 2 ΚΩ 3 mA ( 4 ΚΩ 4 ΚΩ 12 ΚΩ
Thevenin's theorem. A circuit produces voltage V on open circuit. When it is measured with a voltmeter having an impedance of 20 k2, the volt- meter reads 15 V; when the voltmeter is switched to a range having an impedance of 50 k2, it reads 18 V. What is V2
s Find vo in the circuit shown in Fig.P3. using Thevenin's Theorem. vA/5 10? + DA 10? 50 V 30 ? 39 ? 78 ?
#1. Use Thevenin's Theorem to find the voltage V, in the circuit below. 3 Ω 2Ω Ο Ο + 50 V 6Ω Σ 0.5υ, & 10 Ω ob
Calculate the small-signal voltage gain vo/ v, in the circuit shown below. (20 pts) 5. Ik 2 iB 2 KR 5k12
Apply Thevenin's theorem to find V, in the given circuit where I = 6.5 A. 10 162 0w 101 { v. The value of V, in the given circuit is References eBook & Resources
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K2, R2=8 K12, R3=3.8 KS2, R4=6 KI2, R5=15 KS2, R6=3.8 KN, RL=9.8 K12, V1=1V, 12=0.5 mA and V3=2.2 V. } R6 R1 w R5 w + Vo + } RL 12 R2 V1 R3 R4 + +1 V3 Using the above circuit, but consider the following component values: R1= 2 KN R2=8 K2, R3=4.1 K12, R4=6 KI2, R5=17.0 K12, R6=15 KI, RL=10 KI, V1=1V, 12=0.5mA...
Use Thevenin's theorem to find Vo in the network. 6ΚΩ 6V 12V
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K12, R2=8 KN, R3=3.9 KN, R4=6 KN, R5=18 K2, R6=4.4 KN, RL=12.5 KN, V1=1V, 12=0.5 mA and V3=3.4 V. R6 R1 R5 Vo + + RL R2 V1 R3 R4 + V3 Answer: LOV Using the above circuit, but consider the following component values: R1= 2 KO2 R2=8 K12, R3=3.6 K12, R4=6 K12, R5=16.9 KN, R6=15 KN, RL=10 KO, V1=1V, 12=0.5mA and V3=2V. What is...