Question

can someone please fo through the steps?

2. Circle the solution with the highest concentration. Show your calculation to determine the molarity of each solution (you may not need all provided information). (15 points) Solution Molarity (M) Calculation: 35 mt aqueous solution containing 2.6 grams of KCI (solution density = 1.05 g/mL) 0.500 L aqueous solution containing 263 grams CaBrz (solution density = 1.11 g/mL) 154 mmoles (NH4)2SO4 in 48 ml of an aqueous solution (solution density = 1.03 g/mL) 5.3% (m/v) solution of NaOCI 192 (solution density = 1.07 g/mL) 3.0% (m/m) solution of Naci (solution density = 1.03 g/mL) 58.443 Page 1 of 2

Answer 1

| 35 m2 Solution of All instant Volume of solution = 35mL = 35X103 L = 0.035 L mass of kce = 2.6 g Molas mass & kul = 74.55 Ilmoie dont mole of kll = mass = 2.6 Molar mass 74.55 = 0.048 mole Molanty = mole Volume in a than Molarity = ni 0.0348 01035 = ogg42 M

Volume = 0.5 L mass & Caßra = 263 g molar mass of Cabr2 = 199.88 Ilmore mole d cabra = 263 = 1.3157 mass a D 199.88 Melesity = 1.3157 = 216314 H 0.5

154 m mole (NH4), sou in 48 mL Volume = 48 ML = 48 L = 0.048 L looo milimole 154 than [• 1 mili molestie. more] mole = 154 mole mo 1000 4 1 milimole = Mole looo - 01154 mole Molasity = 0.154 O.048 = 3.2083 M

6 15.3 % (m/l Solution of Naoce means 100 mL solution containing 5.3 g Naoce Volume = 100 mL = loo l zooli mass of Naoce = 5.3 g Molar mass of Nao Q = 74.44 Ilmale mole = 53 = 0.07|| mole 74,44 Molarity = mole 0.071 Volume ina = 0.711 M 0:1

solution of Nach 3.0 % mlm means 100 g mass of Nace Molar mass mole = Nace Solution containg 3 g = 3 g & Nace a 58.nu gimole 3 - 30.0513 mole mass of solution = density = massa 100 g, density = 1:03 9/mL . Volume than a Volume of solution = mass density 100 g = 97.0873 1003 g/m2 2 97.0873 ML = 97.0873 L = 0.09708,L Molasity - mole Volume 0.0513 00gton = 0.5284 M - solution ③ hax highest molarity