Question

question 4 & 5

Question 4 (2 points) if you accidently read the procedure wrong while doing the synthesis of aspirin and mixed Sg of salicylic acid with 2 mL of acetic anhydride (instead of correctly mixing 2g of salicylic acid with 5 mL of acetic anhydride), what would be the effect7(density of acetic anhydride = 1.082 g/mL) a Nothing, it would still work just fine Ob Reaction would work fine, but less product would form since acetic anhydride is now the limiting reagent OC Reaction would work fine, but more aspirin would be made since you started with more salicylic acid Od No reaction would occur Question 5 (5 points) In this lab, you will synthesize aspirin (acetylsalicylic acid) from salicylic acid and acetic anhydride. if you react 3.26g of salicylic acid (molar mass - 138.12 g/mol with an excess of acetic anhydride and find that you make 2.145g of aspirin (molar mass - 180.16 g/mol), what is your percent yield? Report your answer as a percentage with I decimal place. Blank 1:

Answer 1

Comment in case of any doubt.

acid 6 Acetic anhydride and salicylic acid react in tit molar ratio to produce 1 mol aspirin. That is : salicyle acid + acetic drade Aspirin to acetic - anhydride (138-12 g/mol) (102.09g) (180.169 ) molar mass Product 15g salicylic acids in 0.0362 mat salicylic acid amburint amb acetic anhydrid=2 mLX 1.0829 = 2.18g = 21649* immedoge = 0.0212 mud acetic anhydride 0.0212 us 2g salicyki and = ag = 0.0145 mal salicylic 1. 138-12 g/mol 1/ило obtained m2 mould 102.099 acid Grool acetic anhydride = 5mL X1-0829 mi Y nad 0.053 mo obtained would be L o.olus mol anhydride 102.09 acetic , O 1 Thus, product obtained is more than the procedure prescribed and this answer is (c) ② moles of salicylic acid in 3.26g= 3.269x 1 mol = 0.0236 1 138.12g mal so, theoretical yield of aspirin = 0.0236 max 180.169 = 4.252g % yeld = actual geld x100= 2.145 gx100=50.4% / theoretic yield 4.2529 Thus percent yield is 50.4% 1.