Question

For the aqueous Hg(NH), complex K, = 1.8*10 at 25°C. Suppose equal volumes of 0.0026 M Hg(NO), solution and 0.20 M NH, solut
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Answer #1

Initial Concentration of Hg2+ after mixing = 0.0026M/2 = 0.0013 M and concentration of NH3 = 0.20/2 = 0.10M

As formation constant is very large , most of Hg2+ would convert into complex form .

Hg2+ +. 4 NH3\leftrightharpoons.   [Hg(NH3)4]2+ Kf = 1.8×1019

x. (0.1-0.0013×4)M. 0.0013M

1.8×1019 = 0.0013/(x * (0.0948)4)

x = 0.0013/(0.09484 × 1.8×1019) = 8.942×10-19

[Hg2+] = 8.9×10-19 M. (Answer)

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