Let initial mass = 100 g
final mass = 3.1 g
And n be the number of half life
Initial mass/final mass = [2}^n
100/ 3.1 =[2}^n
Then n=5
option D
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Ag2SO3 ---> 2Ag+ + SO32-
given solubility = 4.6x10^-3 g/L convert this to mols/L,by dividing
with molar mass
4.6x10^-3 g/L/295.80 mols/g = 0.01555 x10^-3 mols/L
Ksp = [Ag}^2{SO32-}
=[ 2*0.01555 x10^-3 mols/L]^2*0.01555 x10^-3 mols/L
= 1.5 x10^-5+-3+-6 = 1.5 x10^-14
Ksp = 1.5 x10^-14
option C
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18)
correct statements are
B) Dynamic equilibrium occurs when rate of forward reaction = rate
of reverse reaction
Only one statement is correct
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16) How many half-lives are required for the concentration of reactant to decrease to 3.1% of its original value? A...
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