CODE:
Bisect
function [n,alpha]=bisect(a,b,eps)
alpha=(a+b)/2;
n=1;
fval=f(alpha);
while (b-alpha> eps) & (fval ~= 0)
fa=f(a);
if fa*fval< 0
b=alpha;
else
a=alpha;
end
alpha=(a+b)/2;
n=n+1;
fval=f(alpha);
end
end
newton
function [n,alpha]=newton(x0,eps,maxits)
alpha=x0;
[fval,deriv]=func(alpha);
n=0;
while (abs(fval) > eps) & (n <= maxits)
alpha=alpha-fval/deriv;
n=n+1;
[fval,deriv]=func(alpha);
end
end
f
function y=f(w)
%i am assuming d=6 you can change it in the line below
d=6;
y=9.8*(exp(24*w)-1)/(w*(exp(24*w)+1))-d;
end
func
function [f,fdash]=func(w)
d=6;
f=9.8*(exp(24*w)-1)/(w*(exp(24*w)+1))-d;
fdash=9.8*(24*(exp(24*w)*(w*(exp(24*w)+1)))-(exp(24*w)-1)*((exp(24*w)+1)+w*(exp(24*w)*24)))/((w*(exp(24*w)+1))^2);
end
last digit is 5 bisect f.m newton.m func.m 2(a) Let d be the last digit of your student ID number. But if d0, t...
Hi, we recently had an assignment and I ended up skipping this question because I didn't understand the question nor how to even start it. Obviously for Matlab! Coding is not my strong point so this was a stitch up. The data we were meant to use is below! For (a) function [n,alpha]=bisect(a,b,eps) alpha=(a+b)/2 n=1; fval=f(alpha); while (b-alpha> eps) & (fval ~= 0) fa=f(a); if fa*fval< 0 b=alpha; else a=alpha; end alpha=(a+b)/2 n=n+1; fval=f(alpha); end end Sample f.m function y=f(w)...
in matlab -Consider the equation f(x) = x-2-sin x = 0 on the interval x E [0.1,4 π] Use a plot to approximately locate the roots of f. To which roots do the fol- owing initial guesses converge when using Function 4.3.1? Is the root obtained the one that is closest to that guess? )xo = 1.5, (b) x0 = 2, (c) x.-3.2, (d) xo = 4, (e) xo = 5, (f) xo = 27. Function 4.3.1 (newton) Newton's method...
____________ % This function is a modified versio of the newtmult function obtained % from % “Applied Numerical Methods with MATLAB, Chapra, % 3rd edition, 2012, McGraw-Hill.” function [x,f,ea,iter]=newtmult(func,x0,es,maxit,varargin) % newtmult: Newton-Raphson root zeroes nonlinear systems % [x,f,ea,iter]=newtmult(f,J,x0,es,maxit,p1,p2,...): % uses the Newton-Raphson method to find the roots of % a system of nonlinear equations % input: % f = the passed function % J = the passed jacobian % x0 = initial guess % es = desired percent relative error...
This is Matlab Problem and I'll attach problem1 and its answer for reference. We were unable to transcribe this imageNewton's Method We have already seen the bisection method, which is an iterative root-finding method. The Newton Rhapson method (Newton's method) is another iterative root-finding method. The method is geometrically motivated and uses the derivative to find roots. It has the advantage that it is very fast (generally faster than bisection) and works on problems with double (repeated) roots, where the...
Newton's Method in MATLAB During this module, we are going to use Newton's method to compute the root(s) of the function f(x) = x° + 3x² – 2x – 4 Since we need an initial approximation ('guess') of each root to use in Newton's method, let's plot the function f(x) to see many roots there are, and approximately where they lie. Exercise 1 Use MATLAB to create a plot of the function f(x) that clearly shows the locations of its...