Hi, we recently had an assignment and I ended up skipping this question because I didn't understand the question nor how to even start it. Obviously for Matlab! Coding is not my strong point so this was a stitch up. The data we were meant to use is below!
For (a)
function [n,alpha]=bisect(a,b,eps) alpha=(a+b)/2 n=1; fval=f(alpha); while (b-alpha> eps) & (fval ~= 0) fa=f(a); if fa*fval< 0 b=alpha; else a=alpha; end alpha=(a+b)/2 n=n+1; fval=f(alpha); end end
Sample f.m
function y=f(w) y=cos(w)-w; end
For (b)
function [n,alpha]=newton(x0,eps,maxits) alpha=x0; [fval,deriv]=func(alpha); n=0; while (abs(fval) > eps) & (n <= maxits) alpha=alpha-fval/deriv n=n+1; [fval,deriv]=func(alpha); end end
func.m
function [f,fdash]=func(w) f=cos(w)-w; fdash=-sin(w)-1; end
I have assumed d=6 but u can change it to yours just by changing it int f.m and func.m
Since the codes were given you were only supposed to find a and b values. '
we can see if we put w<-1 then the fraction is approximately -9.8
which would be < d irrespective of d.
similarly id w>1 then the fraction is>9.8 and faction>d irrespective of d.
You only need to change f and func corresponding to this function and call bisection and newton raphson code.
We can see newton Raphson takes much less iterations to complete
here are the codes:-
Bisect
function [n,alpha]=bisect(a,b,eps)
alpha=(a+b)/2;
n=1;
fval=f(alpha);
while (b-alpha> eps) & (fval ~= 0)
fa=f(a);
if fa*fval< 0
b=alpha;
else
a=alpha;
end
alpha=(a+b)/2;
n=n+1;
fval=f(alpha);
end
end
newton
function [n,alpha]=newton(x0,eps,maxits)
alpha=x0;
[fval,deriv]=func(alpha);
n=0;
while (abs(fval) > eps) & (n <= maxits)
alpha=alpha-fval/deriv;
n=n+1;
[fval,deriv]=func(alpha);
end
end
f
function y=f(w)
%i am assuming d=6 you can change it in the line below
d=6;
y=9.8*(exp(24*w)-1)/(w*(exp(24*w)+1))-d;
end
func
function [f,fdash]=func(w)
d=6;
f=9.8*(exp(24*w)-1)/(w*(exp(24*w)+1))-d;
fdash=9.8*(24*(exp(24*w)*(w*(exp(24*w)+1)))-(exp(24*w)-1)*((exp(24*w)+1)+w*(exp(24*w)*24)))/((w*(exp(24*w)+1))^2);
end
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