Question

ollowing electronic transitions in a hydrogen atom will result 23) D) C>D>A>B E) D>A>C>B 23) For which of the following ele in the emission of light of the highest energy? A) n=5 to n=1 B) n = 4 to n = 2 C) n=5 to n=3 D) n=1 to n=5 E) n=2 to n=4 24) Choose the valence orbital diagram that represents the ground state of Se?. A) 24) Зр 3s 3p 4P 25) 25) Identify the most reactive alkali metal A) K B) Rb C) Li D) CS E) Na

Answer 1

23) Emission of light takes place when electronic transition from highen to lowen enengy level takes place. Highest amount of emilled energy will connespond to Transition from highest n-value to lowest n-value tramition. So keeping the above two point in mind, the answer will be | A) n=5 to n-1 24) Se 2- has total electron = 34+2 = 36 .. Electronie configuration of sea is — 1522s22p6 352 3p6 3110 4824p6 So the auswen is e) . (1117) 4P 25) The alkali metal series is – 口呈xast As reactivity increases down the group, due to large atomic size and ease of losing electrou, 'CS: is the most reactive alkali metal. C'Fr' is not considened as reactive in this sewe due to its radioactive nature.) So, the ansier is D) CS