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3. Suppose a farmer wants to build a rectangular enclosure along an existing stone wall. If the side along the wall needs no
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- length of wall = 1 length of other side = b c = 500 = 2 bt e lt2b = Soo le 500-26 1 A = Areas rectangle = ex b = (50o-2b) x

et 2b = soo l = 500-26 A = Area of rectangle = = exb (soo-2b) xb = Soob - 262 maximising area by finding derivative = JA db 5

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