Electrolysis equation is:
Ag1+ + 1e- ------>
Ag
1 mol of Ag requires 1 mol of electron
1 mol of electron = 96485 C
So,1 mol of Ag requires 96485 C
let us calculate the charge passed:
t = 72.0 min = 72.0*60 s = 4.32*10^3 s
time, t = 4.32*10^3s
Q = I*t
= 6.8A * 4.32*10^3s
= 2.938*10^4 C
mol of Ag plated = 2.938*10^4/96485 = 0.3045 mol
Molar mass of Ag = 1.079*10^2 g/mol
mass of Ag = number of mol * molar mass
= 0.3045 * 1.079*10^2
= 32.84 g
Answer: 32.84 g
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