Solution:
The system would include:
The puck, ramp, spring and the earth
Explanation:
1/2 kx^2 = Energy at point A
and
mgh + 1/2 mv^2 + 1/2 Mv^2 = Energy at point B
now;
1/2 kx^2 spring
1/2 Mv^2 ramp Kinetic energy
1/2 mv^2 puck's kinetic energy
mgh potential energy between earth and puck
here; g= G(Mass of earth) / (radius of earth)^2
Direct Measurement Video: Dry-ice levitated puck on a ramp 5 of 5> Part D Assuming there is no friction,...