Question

Consider the combustion reaction for octane (CH2), which is a primary component of gasoline. 2CH3 + 250, 1600, + 18H,0 How ma
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Answer #1

Molar mass of C8H18,

MM = 8*MM(C) + 18*MM(H)

= 8*12.01 + 18*1.008

= 114.224 g/mol

mass of C8H18 = 14.6 g

mol of C8H18 = (mass)/(molar mass)

= 14.6/1.142*10^2

= 0.1278 mol

According to balanced equation

mol of CO2 formed = (16/2)* moles of C8H18

= (16/2)*0.1278

= 1.023 mol

Answer: 1.02 mol

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