Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O How many moles of CO2 are emitted into the atmosphere when 26.6 g C8H18 is burned?
Molar mass of C8H18,
MM = 8*MM(C) + 18*MM(H)
= 8*12.01 + 18*1.008
= 114.224 g/mol
mass of C8H18 = 26.6 g
mol of C8H18 = (mass)/(molar mass)
= 26.6/1.142*10^2
= 0.2329 mol
Balanced chemical equation is:
2C8H18+25O2⟶16CO2+18H2O
According to balanced equation
mol of C02 formed = (16/2)* moles of C8H18
= (16/2)*0.2329
= 1.863 mol
Answer: 1.86 mol
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O How...
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O How many moles of CO2 are emitted into the atmosphere when 25.6 g C8H18 is burned?
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