Question

The complete combustion of octane, C8H18, a component of gasoline, proceeds as follows: 2C8H18(l)+25O2(g)→16CO2(g)+18H2O(g)

a. How many moles of O2 are needed to burn 1.35 mol of C8H18?

b. How many grams of O2 are needed to burn 13.0 g of C8H18?

c. Octane has a density of 0.692 g/mL at 20 degrees C. How many grams of O2 are required to burn 1.20 gal of C8H18?

Answer 1

ALLA 16 coleg) + 1 3 H₂O(g) 2. Gattis le+ 25024) صمم we C8H18 reacts of from this reaction equation conclude that a moles with 25 molee of 02. 02 Moles of God Helga Molee of 25 Cinese moles of CoH18 21:35 کن ها رهام وعاصم - 25 Moles of os required : L' 1.35X25 - 16•88 mo) 2 lton • Given- mass of CB H18 = 139 Molecules_mase of CB 1182 11491mol moles of GoHl8 = mass - Molecular mass liaglmol 0.114 mol E i moles_of_0220114_* 25 21:42 5 mol 2 1 gallon : 3785.4ml so, 1.2ogal = 4542.5ml. Given - Density of C8H18 = 0.69291 ml .. mass of collig in 1.2ogal z Density (gim! 2 x volumelmil 0.69291ml x 454205 m).

L OODLE mass 3 31434ge No mass C 8 H 18 of moles of Molecular mass 3143.49 - 27.6 mol 11491 mol .: Moles of O2 = moles of G8 HIZ X 25. Moles of oa = 27.6 Xa5 mol Molee of a = 345 moles at mass of Od required : 345 x Moleculas mass of os! =345 x 32 g = 11,onog
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