The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 442 mol of...

Question

Question

The combustion of octane, C8H18, proceeds according to the reaction shown.

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)

If 442 mol of octane combusts, what volume of carbon dioxide is produced at 19.0 ∘C and 0.995 atm?

?=

Answer 1

Answer #1

268 Hio (1)+250,491–1660249)+18 2014) By nun, Imol Catig produce = 16 mol CO2 * 442 mol C8H18 produce= (16 x 442) mol CO2 = 3

Answer 2

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