28. A 0.50 L buffer solution is 0.20 M in HF and 0.40 M in NaF. The Ka for HF is 1.5 x 10*. Show all work for full...

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Answer 1

Answer #1

Answer:-

This question is solved by using simple concept of Henderson Hasselbalch equation and moles of HF and F^-.

The answer is given in the image,

Answer: de CHF] =0.20M (F-1=0.40M kar), 54104 Ples-loglas log(1.541004) pka = 3.82 0143 of HF = 0.20X0-50 - 0.10 mol. bles p=

Answer 2

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